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EAN-139781164665892   EAN-13 barcode 9781164665892
Product NameHaworth, Past And Present: A History Of Haworth, Stanbury And Oxenhope (1879)
LanguageEnglish
CategoryBook / Magazine / Publication
Short DescriptionPaperback
Amazon.comA Buy on Amazon ~ 1164665898
SKU9781164665892ING
Price New15.17 US Dollars    (curriencies)
Price Used17.27 US Dollars    (curriencies)
Long DescriptionThis book is a facsimile reprint and may contain imperfections such as marks, notations, marginalia and flawed pages.
Created11-21-2012 11:06:32pm
Modified12-23-2013 10:21:30pm
MD557ba8a34394ee4529b40d84f4894f9a6
SHA2567ddc88254627ec47647906c7a147ed490289389dd187be2d269b2be97e89e720
Search Googleby EAN or by Title
Query Time0.0009210

Code 128 is a high-density 1D barcode symbology. This barcode set makes use of the entire 128 ASCII characters which include letter, number and symbols.

Code 128 Barcode

As with all barcodes, there are indicators to identify where the barcode starts and stops. These are marked in yellow below. Code 128 also has a check character which has been marked in green. The remainder of the barcode is the data being encoded. The text below the barcode is optional and is for human consumption in the event the barcode can't be scanned or if people also need to know what the code means.

Code 128 Barcode

Each character in the barcode symbol is composed of three bars and three spaces. Each bar or space must range from 1-4 units and the sum of all the width of all bars must work out to an even number. The stop marker is special because it adds an extra bar of 2 units at the very end (4 bars and 3 spaces). There are three different start markers to to identify which code set is being used. To represent all 128 characters, the code sets can be within a single barcode as needed by using control characters 98-101 (depending on the code set).

The check character is calculated by summing the value of each character and multiplying it by its position. The start character is also part of the sum but is added without weight (multiply by 1 just like the first encoded data character) then when you have the sum take the modulo 103 remainder. This gets a little more complex when mixing modes within a single barcode.

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