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EAN-139780746078792   EAN-13 barcode 9780746078792
Product NameRogues' Gold (Elizabethan Mysteries)
LanguageEnglish
CategoryBook / Magazine / Publication
Short DescriptionPaperback
Amazon.comA Buy on Amazon ~ 074607879X
SKUE9780746078792
Price New69.98 US Dollars    (curriencies)
Price Used0.85 US Dollars    (curriencies)
Width0.67 inches    (convert)
Height7.8 inches    (convert)
Length5.12 inches    (convert)
Weight7.84 ounces    (convert)
AuthorJohn Pilkington
BindingPaperback
Published12/31/2016
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Created11-18-2012 7:17:25am
Modified12-31-2016 5:52:34pm
MD5b672c63b7cb9b4898bdec851118b7b7c
SHA25624563fc61cdaca7f615cb1f0600386c31c65be705a97ef7b9acedda40304619f
Search Googleby EAN or by Title
Query Time0.0075569

Article of interest

Code 128 is a high-density 1D barcode symbology. This barcode set makes use of the entire 128 ASCII characters which include letter, number and symbols.

Code 128 Barcode

As with all barcodes, there are indicators to identify where the barcode starts and stops. These are marked in yellow below. Code 128 also has a check character which has been marked in green. The remainder of the barcode is the data being encoded. The text below the barcode is optional and is for human consumption in the event the barcode can't be scanned or if people also need to know what the code means.

Code 128 Barcode

Each character in the barcode symbol is composed of three bars and three spaces. Each bar or space must range from 1-4 units and the sum of all the width of all bars must work out to an even number. The stop marker is special because it adds an extra bar of 2 units at the very end (4 bars and 3 spaces). There are three different start markers to to identify which code set is being used. To represent all 128 characters, the code sets can be within a single barcode as needed by using control characters 98-101 (depending on the code set).

The check character is calculated by summing the value of each character and multiplying it by its position. The start character is also part of the sum but is added without weight (multiply by 1 just like the first encoded data character) then when you have the sum take the modulo 103 remainder. This gets a little more complex when mixing modes within a single barcode.

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